p^2-14p-100=-5

Solution for p^2-14p-100=-5 equation:

p^2-14p-100=-5

We move all terms to the left:

p^2-14p-100-(-5)=0

We add all the numbers together, and all the variables

p^2-14p-95=0

a = 1; b = -14; c = -95;
Δ = b2-4ac
Δ = -142-4·1·(-95)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-24}{2*1}=\frac{-10}{2}
=-5
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+24}{2*1}=\frac{38}{2}
=19
$